[simpits-tech] electrical ??

[Andreas Fransson]

(disclamer: my high school electrical skills may be a bit rusty...)

IIRC...

P=UI (watts = volts x amps)
I=U/R (amps = volts / ohms)
=>
P=U^2/R (watts = volts(square) / ohms)

You have already concluded that the panel has a 0.5 ohm resistance, and is
rated at 5 volts. This means that it draws 5^2/0.5=50 watts at that voltage.
That seems to me to be a whole lot...

At 5 volts, the current should be 5/0.5=10 amps...

Someone please correct me if I have gotten all of this backwards. ;)

Andreas
http://valhallainc.d2g.com


From: "Dave Hensley" <dphens@nc.rr.com>
> I need a little assistance with a power problem. I am trying to determine
> the amount of amps I need going through the panels I have to light them
up.
> The panels are rated for 5vdc. I plugged in a 6vdc adapter which is
putting
> out 7.70v before anything is connected, measured with a mutlimeter. Then I
> connected leads to the adapter and the panel, while leaving the leads for
> the multimeter connected also. The volts in the multimeter dropped to
4.41v.
> Next I connected only the meter to the panel set to measure resistance and
> had a reading that fluctuated between .4 to .6, so I split the difference
at
> .5. So, using V=I*R formula, 7.70/.5=3.85. So, the lights are pulling
almost
> 4 amps? Am I even close to having that right?
>
> Obviously you guys are seeing that I know very little about this and am in
> the process of learning. I am playing with the panel in an attempt to
> understand the relationship of volts, current and resistance. If am I way
> off at this point, I'll stop and do some more reading. I am just hoping I
am
> on the right track. :-)
>
> Thanks!
>
> Dave