ignorance is bliss, <br>first your rotary is not a pot. pots are resistors. the encoder generates pulses.<br>If you have your hart in doing this and you want outputs that go from 0 - 5vdc, the <br>use 2 open collector gates, no diodes, no R-divider, no nothing.<br>
you need a switch (two, one for each, forward, backwards, so when you close this <br>you turn on a TTL gate with open collector outputs on (5v) this device requires a 5vdc source for the output through a small value of R say 1k your output is at the junction<br>
of the resistor, and the gates output. DONE <br>CH<br><br><div class="gmail_quote">On Fri, Mar 13, 2009 at 3:16 AM, Jeroen Huijben <span dir="ltr"><<a href="mailto:jeroen_huijben@hotmail.com">jeroen_huijben@hotmail.com</a>></span> wrote:<br>
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It has to mimick a pot.<br>
What I want is to turn the G25 shifter into three rotaries and this shifter is read by two pots.<br>
The rotaries are processed by two flipflops each which should pull only one output high.<br>
<a href="http://www.interq.or.jp/japan/se-inoue/e_ckt10_3.htm" target="_blank">http://www.interq.or.jp/japan/se-inoue/e_ckt10_3.htm</a><br>
That signal is then sent to the right transistors through diodes to prevent crosstalk.<br>
<br>
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Date: Thu, 12 Mar 2009 19:26:14 -0500<br>From: <a href="mailto:phoenixcomm@gmail.com" target="_blank">phoenixcomm@gmail.com</a><br>To: <a href="mailto:simpits-tech@simpits.org" target="_blank">simpits-tech@simpits.org</a><br>
Subject: Re: [simpits-tech] Electronics question<div class="im"><br><br><font color="#0070c0">jeroen,<br>This is the Hardway<br>seems like you overherd of Open Collector, outputs<br>1. put 5vdc on the collector through a small resistor like 330ohms,<br>
put your lamp/what ever between the resistor and the open collector now you can pull this down with a gate if you want to, tada<br>Cris Harrison</font><br>
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From: <a href="mailto:crease-guard@sbcglobal.net" target="_blank">crease-guard@sbcglobal.net</a><br>To: <a href="mailto:simpits-tech@simpits.org" target="_blank">simpits-tech@simpits.org</a><br>Date: Thu, 12 Mar 2009 13:14:35 -0500<br>
Subject: Re: [simpits-tech] Electronics question<div><div></div><div class="h5"><br><br>
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<p><font color="navy" size="2" face="Arial"><span style="font-size: 10pt; color: navy; font-family: Arial;">So the A and B are used to open the base of the transistor to pull “X” to 5v or ground, correct? Will your circuit work with “X” at 2.5 volts…i.e. neither high nor low? How is “X” being measured/monitored?</span></font></p>
<p><font color="navy" size="2" face="Arial"><span style="font-size: 10pt; color: navy; font-family: Arial;"> </span></font></p>
<p><font color="navy" size="2" face="Arial"><span style="font-size: 10pt; color: navy; font-family: Arial;">Also, make sure both transistors don’t open at the same time.</span></font></p>
<p><font color="navy" size="2" face="Arial"><span style="font-size: 10pt; color: navy; font-family: Arial;"><br>Jay</span></font></p>
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<p><b><font size="2" face="Tahoma"><span style="font-weight: bold; font-size: 10pt; font-family: Tahoma;">From:</span></font></b><font size="2" face="Tahoma"><span style="font-size: 10pt; font-family: Tahoma;"> <a href="mailto:simpits-tech-bounces@simpits.org" target="_blank">simpits-tech-bounces@simpits.org</a> [mailto:<a href="mailto:simpits-tech-bounces@simpits.org" target="_blank">simpits-tech-bounces@simpits.org</a>] <b><span style="font-weight: bold;">On Behalf Of </span></b>Jeroen Huijben<br>
<b><span style="font-weight: bold;">Sent:</span></b> Thursday, March 12, 2009 10:13 AM<br><b><span style="font-weight: bold;">To:</span></b> Simpits List<br><b><span style="font-weight: bold;">Subject:</span></b> [simpits-tech] Electronics question</span></font></p>
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<p style="margin-bottom: 12pt;"><font size="2" face="Verdana"><span style="font-size: 10pt; font-family: Verdana;">I am wondering if this will work.<br> <br>I have a voltage divider of two resistors, set to put 2.5V at the output X when 5V is set over it.<br>
I want to use a logic chip (74HC74 dual Dtype flipflop) to pull the output to 0V or 5V, depending on how a rotary encoder turns.<br>I have found how to turn the signal of the rotry into a high on either of two outputs of the flipflop.<br>
Now I want to use two transistors to short out either of the resistors so that the output X is connected to either side of the divider.<br> <br><a href="http://i40.tinypic.com/jajuag.gif" target="_blank">http://i40.tinypic.com/jajuag.gif</a><br>
A and B will go straight to the chip with only a diode in between.<br> <br>Will this work?<br>Can I use any regular transistor?<br><br>Regards,<br>Jeroen.</span></font></p>
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