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<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'>So the A and B are used to open the base
of the transistor to pull “X” to 5v or ground, correct? Will your
circuit work with “X” at 2.5 volts…i.e. neither high nor
low? How is “X” being measured/monitored?<o:p></o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'><o:p> </o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'>Also, make sure both transistors don’t
open at the same time.<o:p></o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'><br>
Jay<o:p></o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'><o:p> </o:p></span></font></p>
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<p class=MsoNormal><em><i><font size=2 color=navy face=Arial><span
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be bothered to do the little things, and I will show you a man who cannot be
trusted to do the big ones.</span></font></i></em><font color=navy><span
style='color:navy'><o:p></o:p></span></font></p>
<p class=MsoNormal><em><i><font size=2 color=navy face=Arial><span
style='font-size:10.0pt;font-family:Arial;color:navy'>--<st1:City w:st="on">Lawrence</st1:City>
<st1:City w:st="on">Bell</st1:City>, Founder <st1:place w:st="on"><st1:City
w:st="on">Bell</st1:City></st1:place> Helicopter</span></font></i></em><o:p></o:p></p>
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<p class=MsoNormal><b><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma;font-weight:bold'>From:</span></font></b><font size=2
face=Tahoma><span style='font-size:10.0pt;font-family:Tahoma'>
simpits-tech-bounces@simpits.org [mailto:simpits-tech-bounces@simpits.org] <b><span
style='font-weight:bold'>On Behalf Of </span></b>Jeroen Huijben<br>
<b><span style='font-weight:bold'>Sent:</span></b> Thursday, March 12, 2009
10:13 AM<br>
<b><span style='font-weight:bold'>To:</span></b> Simpits List<br>
<b><span style='font-weight:bold'>Subject:</span></b> [simpits-tech]
Electronics question</span></font><o:p></o:p></p>
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<p class=MsoNormal><font size=3 face="Times New Roman"><span style='font-size:
12.0pt'><o:p> </o:p></span></font></p>
<p class=MsoNormal style='margin-bottom:12.0pt'><font size=2 face=Verdana><span
style='font-size:10.0pt;font-family:Verdana'>I am wondering if this will work.<br>
<br>
I have a voltage divider of two resistors, set to put 2.5V at the output X when
5V is set over it.<br>
I want to use a logic chip (74HC74 dual Dtype flipflop) to pull the output to
0V or 5V, depending on how a rotary encoder turns.<br>
I have found how to turn the signal of the rotry into a high on either of two
outputs of the flipflop.<br>
Now I want to use two transistors to short out either of the resistors so that
the output X is connected to either side of the divider.<br>
<br>
<a href="http://i40.tinypic.com/jajuag.gif">http://i40.tinypic.com/jajuag.gif</a><br>
A and B will go straight to the chip with only a diode in between.<br>
<br>
Will this work?<br>
Can I use any regular transistor?<br>
<br>
Regards,<br>
Jeroen.<o:p></o:p></span></font></p>
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<p class=MsoNormal><font size=2 face=Verdana><span style='font-size:10.0pt;
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